Question

at 15 degree celsius is heated until the pressure doubled and the volume triple from my original pressure and volume if the original volume is 1000 CC calculate the temperature to which it should be heated​

Answer 1

225 degree is right answer. if not comment me plzzz

Answer 2

Answer:

Temperature = 1740.9 K

Explanation:

Given:

Initial temperature of gas = 17°C

Final pressure of the gas = Double the initial pressure

Final volume of the gas = Triple the initial volume

Original volume = 1000 cm³

To Find:

Final temperature

Solution:

Convert the temperature from °C to K

17 °C = 290.15 K

By the ideal gas equation we know that,

$\sf \dfrac{P_1V_1}{T_1} =\dfrac{P_2V_2}{T_2}$

where P is the pressure, V is the volume and T is the temperature of the gas.

Substitute the data,

$\sf \dfrac{P_1\times 1000}{290.15} =\dfrac{2\times P_1\times 3\times V_1}{T_2}$

$\sf \dfrac{P_1\times 1000}{290.15} =\dfrac{2\times P_1\times 3\times 1000}{T_2}$

Cancelling 1000 P₁ on both sides,

$\sf \dfrac{1}{290.15} =\dfrac{2\times 3}{T_2}$

$\sf \dfrac{1}{290.15} =\dfrac{6}{T_2}$

Cross multiplying,

T₂ = 6 × 290.15

T₂ = 1740.9 K

Hence the temperature to which the gas should be heated is 1740.9 K.

Answer 3

Answer:

Temperature = 1740.9 K

Explanation:

Given:

Initial temperature of gas = 17°C

Final pressure of the gas = Double the initial pressure

Final volume of the gas = Triple the initial volume

Original volume = 1000 cm³

To Find:

Final temperature

Solution:

Convert the temperature from °C to K

17 °C = 290.15 K

By the ideal gas equation we know that,

$\sf \dfrac{P_1V_1}{T_1} =\dfrac{P_2V_2}{T_2}$

where P is the pressure, V is the volume and T is the temperature of the gas.

Substitute the data,

$\sf \dfrac{P_1\times 1000}{290.15} =\dfrac{2\times P_1\times 3\times V_1}{T_2}$

$\sf \dfrac{P_1\times 1000}{290.15} =\dfrac{2\times P_1\times 3\times 1000}{T_2}$

Cancelling 1000 P₁ on both sides,

$\sf \dfrac{1}{290.15} =\dfrac{2\times 3}{T_2}$

$\sf \dfrac{1}{290.15} =\dfrac{6}{T_2}$

Cross multiplying,

T₂ = 6 × 290.15

T₂ = 1740.9 K

Hence the temperature to which the gas should be heated is 1740.9 K.

Answer 4

Answer:

Temperature = 1740.9 K

Explanation:

Given:

Initial temperature of gas = 17°C

Final pressure of the gas = Double the initial pressure

Final volume of the gas = Triple the initial volume

Original volume = 1000 cm³

To Find:

Final temperature

Solution:

Convert the temperature from °C to K

17 °C = 290.15 K

By the ideal gas equation we know that,

$\sf \dfrac{P_1V_1}{T_1} =\dfrac{P_2V_2}{T_2}$

where P is the pressure, V is the volume and T is the temperature of the gas.

Substitute the data,

$\sf \dfrac{P_1\times 1000}{290.15} =\dfrac{2\times P_1\times 3\times V_1}{T_2}$

$\sf \dfrac{P_1\times 1000}{290.15} =\dfrac{2\times P_1\times 3\times 1000}{T_2}$

Cancelling 1000 P₁ on both sides,

$\sf \dfrac{1}{290.15} =\dfrac{2\times 3}{T_2}$

$\sf \dfrac{1}{290.15} =\dfrac{6}{T_2}$

Cross multiplying,

T₂ = 6 × 290.15

T₂ = 1740.9 K

Hence the temperature to which the gas should be heated is 1740.9 K.