At 15°C. volume of a gas is 360 ml Keeping prcasuro constant, temperature of the gas is increased slowly then at what temperature its volumu will be double of its initial volume
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Answer:
The required temperature will be 576 K or, 303°C.
Step-by-Step Explanation:
T1 = 15°C
= 288 K
V1 = 360 ml
V2 = 2V1
= (360*2) ml
= 720 ml
According to Charles's law,
V1/T1 = V2/T2
360/288 = 720/T2
= 360T2/288 = 720
= T2 = 720*288/360
= T2 = 576 K
or,
= T2 = 303°C
I hope that helps.
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