Question

at 1520mm pressure and 273°c , number of moleculas present in 5.6 litres of a gas are ​

Answer 1

Answer:

6.023×10²³/4

Explanation:

     Given,

          Pressure =1520 mm =2 atm.

         Temperature =273°  C =546 K.

       At 1520 mm pressure and 273°C

              number of moles (n) = PV/RT = 2×5.6 /0.0821 ×546

                                                                 = 1:4  (Ideal Gas Equation)

1 mole contains 6.023×10²³ molecules of it.

         Thus, 1/4 moles of it contains 6.023×10²³ / 4 molecules.

 

​

Answer 2

n=0.25 mol

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