Question

At 17°c osmotic pressure of sugar sol was 580 torr. The sol is diluted and temp is raised to 57°c osmotic pressure become 165torr the extend of dilution is


Ans 4times

Answer 1

Answer:

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Answer 2

The extent of dilution is 4 times.

Given-

• Initial temperature of sugar solution = 17 °C
• Osmotic pressure at 17 °C is = 580 torr
• Final temperature of the sugar solution = 57 °C
• Osmotic pressure at 57 °C is = 165 torr

Here,

T₁ = 290 K

π₁ = 580 torr = 580/760 mm of Hg

T₂ = 330 K

π₂ = 165 torr = 165/760 mm of Hg

We know that osmotic pressure can be given by-

π = CRT where C is the concentration, R is the universal gas constant and T is the temperature.

π₁ = C₁RT₁

π₂ = C₂RT₂

By substituting the values we get

580/760 = C₁ × R × 290 ---------(i)

165/760 = C₂ × R × 330 ----------(ii)

By dividing (i)/(ii)

580/165 = C₁/C₂ × 290/330

C₁/C₂ = 3.515/0.8788

C₁/C₂ = 3.999 ≈ 4 times

C₁ = 4 C₂