At 18°C equivalent conductivities of 0.01N solutions ofHCl acid,NaCl,CH3COONa andCH3COOH are 369.3, 101.7 and 14.3 ohm–1cm2 respectively.Calculate the hydrogen ion concentration in 0.01N acetic acid at 18°C.
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Answer:
As given,
Eq. conductance of CH
3
COOH=369.3−101.7+71.7=339.3
so
α=14.3/339.3=0.041
so hydrogen ion conc.=cα=0.01×0.041=4×10
−4
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