Chemistry, asked by jaykumar5050, 8 months ago

At 2:98 Kelvin the pure water has a vapour pressure 2820 5MM calculate the vapour pressure of solution containing 5 g of urea in 180 g of water at 298 Kelvin

Answers

Answered by vidhishagawand2002
1

Answer:

Explanation:

mole of urea = 5/60

= 0.08

mole of water = 180/18

= 10

mole fraction of water

= 10/10.08

= 0.99

vapour pressure of solution= mole fraction of water *vapour pressure  of pure water

= 28205*0.99

= 27922.95 mm

Similar questions