at 20 degree Celsius on 10 gram of non volatile non electrolyte substance in hundred gram of water vapour pressure decreases from 17.535 mm to 17.2 35 mm. calculate molecular weight of solute
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We have lowering of vapour pressure
P
B
0
P
B
0
−P
t
=x
A
moles of water = 5.55moles
moles of non-volatile solute = x
so we have
17.3555
17.3555−17.235
=
x+5.55
x
x = 0.039
molecular weight of solute =
0.039
10
= 257.45
I hope this helps you
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