Physics, asked by adityavohra12, 8 months ago

At 200 km track a train travels first 50 km at a uniform speed of 40 km/h how far the train was travelling the next 150 km so as to maintain the average speed of 60 km/h for the whole journey

Answers

Answered by AgrataaVasudev
2

Answer:

The train’s speed by maintaining the average speed 60 km/hr for the next 150 km is 72 km/hr.

Given:

Initial distance = 50 km

Total distance = 200 km

Speed = 40 km/h

To find:

The fast of the train to cover next 150 km so as to maintain the average speed of 60 km/h

Solution:

For first 50 km, the speed is 40 km/hr =\frac{50}{40}=\frac{5}{4} \ \mathrm{km} / \mathrm{hr}=

40

50

=

4

5

km/hr

Let x be the km for the next 150 km.

\text { Time taken for the } 150 \ \mathrm{km}=\frac{150}{x} \ \mathrm{hr} Time taken for the 150 km=

x

150

hr

\text{Total time taken} =\frac{5}{4}+\frac{150}{x}=\frac{5 x+600}{4 x} h rTotal time taken=

4

5

+

x

150

=

4x

5x+600

hr

\text { Average speed }=\frac{\text { Total distance }}{\text { Total time taken }} Average speed =

Total time taken

Total distance

\Rightarrow 500 x=36000⇒500x=36000

\Rightarrow x=\frac{36000}{500}⇒x=

500

36000

\therefore x=72 \ \mathrm{km} / \mathrm{hr}∴x=72 km/hr

Explanation:

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