Chemistry, asked by shehroz68, 19 days ago

at 210 gas has volume of 8.00L.What is temperature of gas if its volume increased to 16.00L

Answers

Answered by vindobhawe

0

105 K

Explanation:

Given:

V₁ = 8 L , V₂ = 16 L

T₁ = 210 K , T₂ = ?

At constant pressure, according to Charle's law

V₁ / T₁ = V₂ / T₂

Hence, T₂ = V₂ × T₁ / V₁

= 8 × 210 / 16

= 105 K

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