Question

at 23°c,the vapour pressure of pure water 23.70 mm hg and that of an aqueous dilute solution of urea is 22.98 mm hg.calculate the molality of the solution​

Answer 1

Answer:

Relative lowering in vapor pressure =

P

∘

P

∘

−P

s

=

M

1

×w

2

w

1

×M

2

Here 1 denotes urea and 2 denotes H

2

O.

∴

25

25−20

=

M

1

×w

2

w

1

×18×10

−3

……[w

2

in Kg]

∴

25

5

×

18

1000

=

M

1

×w

2

=Molality

w

1

∴Molality=11.11M

Explanation:

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