Question

At 25 c required volume of water, to dissolve 1g baso4 will be

Answer 1

Answer : he required volume of water to dissolve 1 g BaSO4 is 412 L

BaSO4 is an insoluble solid. Its dissociation reaction can be written as ,

$BaSO_{4} (s)\rightarrow Ba^{2+} (aq) + SO_{4}^{2-} (aq)$

Let "s" be the concentration of BaSO4 at 25 C. From the dissociation equation, we have [Ba²⁺] = s and [SO₄²⁻] = s

Solubility product for BaSO4 is

$Ksp = [Ba^{2+}][SO_{4}^{2-}]$

From the standard reference table, we have Ksp of BaSO4 as 1.08 x 10⁻¹⁰

Let us plug in these value in the Ksp equation.

$1.08 \times 10^{-10} = s^{2}$

s = 0.0000104M

Concentration of BaSO4 at 25 C is 0.0000104 M

We have 1 g of BaSO4.  Let us set up an equation to find out the amount of water needed to dissolve it.

We will use molar mass of BaSO4 to convert 1 g BaSO4 to moles. Then we will use the concentration of BaSO4 to find the amount of water needed.

The set up is given below.

$1 g BaSO_{4}\times \frac{1mol}{233.4g}\times \frac{1L}{0.0000104mol}= 412 L$

The required volume of water to dissolve 1 g BaSO4 is 412 L

Answer 2

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