Chemistry, asked by syedasufia29814, 9 months ago

at 25 degree Celsius ionic product of water is 1*10^-14.how to calculate it???

Answers

Answered by npks1974

0

Answer:

55.5moles

Explanation:

The value of Kw at 25°C is 1 x 10-14. Since pure water is neutral in nature, H+ ion concentration must be equal to OH- ion concentration. This shows that at 25°C, in 1 litre only 10-7 mole of water is in ionic form out of a total of approximately 55.5 moles.

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