Question

At 25 degree celsius of 0.01 mole sample of a gas is compressed from 421 litre at constant temperature what is the work done for this process if the external pressure is 4 bar

Answer 1

Answer: The work done for the given process is 120 Joules

Explanation:

To calculate the amount of work done for an isothermal process is given by the equation:

$W=-P\Delta V=-P(V_2-V_1)$

W = amount of work done = ?

P = pressure = 4 bar = 3.95 atm       (1bar=0.99atm)

$V_1$ = initial volume = 4 L

$V_2$ = final volume = 1 L

Putting values in above equation, we get:

$W=-3.95atm\times (1-4)L=11.85L.atm$

To convert this into joules, we use the conversion factor:

$1L.atm=101.33J$

So, $11.85L.atm=11.85\times 101.3=1200J$

The positive sign indicates the system is doing work.

Hence, the work done for the given process is 1200 Joules.