Question

at 25 degree the half life of decomposition of h202 is 50min. if 4mh202 is present amount h202 left after 200min. is

Answer 1

Answer:

=6.93×10

−4

mol/min

Explanation:

2H

2

O

2

→2H

2

O+O

2

In 50 minutes, the concentration is reduced to one fourth

(∵

0.125

0.5

=4)

Hence 2 half life periods correxponds to 50 minutes.

t

1/2

=25 min

The rate constant k=

t

1/2

0.693

=

25

0.693

Rate of decomposition of H

2

O

2

=k[H

2

O

2

]=

25

0.693

×0.05=1.39×10

−3

mol/min

Rate of formation of oxygen is one half the rate of decomposition of H

2

O

2

.

It is

2

1

×1.39×10

−3

=6.93×10

−4

mol/min

I hope this answer helps you..

thanks