Question

At 25°C, an aqueous solution containing 35.0 wt% H2SO4 has a specific gravity of 1.2563. A quantity of the 35% solution is needed that contains 195.5 kg

Answer 1

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Answer 2

Answer:

a) volume₁ = 444.6 L  

b) Volume₂ = 306 L  and percentage Error = 31.2%

Explanation:

Given that;

the solution contains 35.0 wt% H₂SO₄

A quantity of the 35% solution is needed that contains 195.5 kg of H₂SO₄

Let's say the mass of solution containing 195.5 kg H₂SO₄ is 'A' kg

Now since the question says it is a 35% wt solution,

so

(35/ 100) × Akg = 195.5kg

0.35A = 195.5

A = 558.6kg

So A = 558.6 kg

therefore mass of the  solution is 558.6kg

a)

also, Specific gravity is 1.2563

since density of water = 1kg/ L

density of solution = SG of H₂SO₄ × density of water

therefore density of solution = 1.2563 ×1kg/ L  = 1.2563 kg/ L

Now to calculate the required volume (L) of the solution

we say;

Volume of solution = mass / density

Volume = 558.6kg / 1.2563kg/L

Volume₁ = 444.6 L  

b)

Now If the pure-component specific gravity is to be used,

Specific Gravity = 1.8255

which means Density will be  = 1.8255 kg/ L

Therefore will be

Volume = 558.6kg / 1.8255kg/L

Volume₂ = 306 L

To calculate the error

we say volume₁ - volume₂

Error = 444.6L - 306L = 138.6

So

Percent error = ( 138.6L / 444.6L) × 100

percentage Error = 31.2%