Question

At 25°C for complete combustion of 5 mole of propane. The required volume of O2 at Stp will be:

Answer 1

560l

The required volume of O2 at Stp will be: 1) 560l.

Answer 2

$\huge\sf\pink{Answer}$

☞ Your Answer is 560 L

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$\huge\sf\blue{Given}$

✭ Temperature = 25°C

✭ Number of moles of propene = 5 mole

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$\huge\sf\gray{To \:Find}$

◈ The required Volume of $\sf O_2$

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$\huge\sf\purple{Steps}$

☯ $\underline{\textsf{As Per the Question}}$

➠ $\sf C_3H_8+O_2 \dashrightarrow CO_3+H_2O$

➠ $\small\underline{\underline{\sf C_3H_8+5O_2 \dashrightarrow 3CO_2 + 4H_2O}}$

The chemical symbols represent,

◕ $\sf C_3H_8 \ ➝ \ Propane$

◕ $\sf O_2 \ ➝ \ Oxygen$

◕ $\sf CO_2 \ ➝ \ Carbondioxide$

◕ $\sf H_2O \ ➝ \ Water$

From the balanced equation we may observe that for 1 mole of Propane we need 5 mole of Oxygen,so for 5 moles of Propane

➳ $\sf 5\times 5$

➳ $\sf \red{O_2 = 25 \ moles}$

We know that volume of 1 mole of gas at 1 NTP = 22.4 L

$\underline{\boxed{\sf Volume = mole \times 22.4}}$

Substituting the values,

»» $\sf Volume = 25 \times 22.4$

»» $\sf \orange{Volume = 560 \ L}$

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