Question

At 25°C for complete combustion of 5 mole of propane. The required volume of O2 at S.T.P will be :

Answer 1

$\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}$

No. of mole of propane = 5

$\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$

We have to find required volume of $\sf{O_2}$ at STP for complete combustion of the given amount of propane.

$\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$

➝ We can solve this question by stoichiometric calculation.

➝ Stoichiometry deals with the calculation of masses/volume of the reactants and the products involved in a chemical reaction.

◈ Balanced chemical reaction :

$\underline{\boxed{\bf{\purple{C_3H_8+5O_2}\longrightarrow \orange{3CO_2+4H_2O} }}}$

1 mole of propane requires 5 mole of oxygen at STP.

5 mole of propane requires (5×5) = 25 mole of oxygen at STP.

❂ Required volume of oxygen :

$:\implies\tt\:Volume=mole\times 22.4$

$:\implies\tt\:Volume=25\times 22.4$

$:\implies\boxed{\bf{\gray{Volume=560\:L}}}$

Answer 2

$\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}$

No. of mole of propane = 5

$\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$

We have to find required volume of \sf{O_2}O2​ at STP for complete combustion of the given amount of propane.

$\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$


➝ We can solve this question by stoichiometric calculation.

➝ Stoichiometry deals with the calculation of masses/volume of the reactants and the products involved in a chemical reaction.

◈ Balanced chemical reaction :

\underline{\boxed{\bf{\purple{C_3H_8+5O_2}\longrightarrow \orange{3CO_2+4H_2O} }}}C3​H8​+5O2​⟶3CO2​+4H2​O​​

1 mole of propane requires 5 mole of oxygen at STP.

5 mole of propane requires (5×5) = 25 mole of oxygen at STP.

❂ Required volume of oxygen :

$\implies\tt\:Volume=mole\times 22.4$
$\implies\tt\:Volume=25\times 22.4$

$\implies\boxed{\bf{\gray{Volume=560\:L}}}$