Question

At 25°C, the length of a sheet of aluminum is 30 cm and the width is 20 cm. Determine the change in area and the final area at 60°C.

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Answer 1

Answer:

The change in area (ΔA) :

ΔA = β A1 ΔT

ΔA = (2 x 10-5 oC-1)(1500 cm2)(40oC)

ΔA = (80 x 10-5)(1500 cm2)

ΔA = 120,000 x 10-5 cm2

ΔA = 1.2 x 105 x 10-5 cm2

ΔA = 1.2 cm2

The final area (A2) :

A2 = A1 + ΔA

A2 = 1500 cm2 + 1.2 cm2

A2 = 1501.2 cm2

Explanation: