At 25°C the saturated vapour Pressure of water
is 3.165 kPa (23.75 mm Hg)
Find the saturated
vapour Pressure
of a 5% aqueous solution of urea
(carbamide) at the same temperature . molar mass
Of urea = 60.05 g mol")
Answers
Answered by
1
Explanation:
Let us consider the problem:
Given that:
W=5g,W
A
=95g,M
B
=60.05gmol
−1
M
A
=18gmol
−1
,P
0
A
=3.165kPa
Putting the values in expression
P
A
o
P
A
o
−P
=
M
B
×W
A
W
B
×M
A
3.165kPa
3.165kPa−P
=
60.05gmol
−1
×95g
5g×18gmol
−1
=0.015
Hence,
P=3.165kPa−0.015×3.165kPa
P=3.118kPa.
Similar questions