At 25°C, the solubility product of Mg(OH), is
1.0 10-11. At which pH will Mg2+ ions start
precipitating in the form of Mg(OH), from a
solution of 0.001 M Mg2+ ions
(A) 9
(B) 10
(C) 11
(D) 8
Please do explain me in details
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At 25°C, the solubility product of Mg(OH)2 is 1.0 × 10^-11. At 25°C, the solubility product of Mg(OH)2 is 1.0 × 10–11
(B) is correct option
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b is the correct option so mark me as brain list answer
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