At 25oC,the resistance of a given wire of length 1m and diameter 0.5m.m is 25ohm .what is the resistivity of the material of the wire at that temperature?
Answers
Answer:
Radius of the cross section of the wire(r) = 0.02 mm. = 0.002 cm. ∴ ρ = 2.62 × 10⁻⁶ Ω-cm. Hence, the Specific Resistance of the Resistivity of the wire is 2.62 × 10⁻⁶ Ω-cm.
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Answer: 127.38 ohms-meter.
Given: Length of wire = 1m, diameter = 0.5mm and resistance is 25 ohms at 25°C.
To Find: Resistivity of the wire.
Step-by-step explanation:
Step 1: Resistance:
A conductor's ability to resist the flow of current through it is known as resistance.
The interaction between the applied voltage and the electric current flowing through it controls it.
Step 2: Resistance of a wire:
A wire's resistance is directly correlated with its length and inversely correlated with its cross-sectional area. Additionally, the conductor's material has an impact on resistance.
Ohm's law explains the fundamental behaviour of electrical circuits. Current, resistance, and voltage are all closely connected.
Resistance is a constant that is unaffected by current or voltage, according to Ohm's law.
If the length, cross-sectional area, and resistivity of the material are known, the resistance of a wire can be computed as follows:
Where R is the resistance, is the resistivity of the wire, L is the length of the wire and A is the area of the cross-section of the wire.
The length of the wire – Longer the wire, the greater its resistance.
The greater the cross-sectional area, the less resistance it experiences.
The material's resistivity determines how resistant it is; the higher the resistivity, the more resistant it is.
Ohm's Law can be used to compute resistance if the voltage and current in a circuit are known.
Step 2:
R = 25 Ω
l = 1 m
d = 0.5 mm
r = 0.25 mm
d = m
Hence, correct answer is 127.38 ohms-meter.
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