Question

At 27 c the combustion of ethane takes place according to the reaction C2H6 + 7/2O2 -> 2CO2 + 3H20

∆E-∆H= ?​

Answer 1

delta H - delta E = delta n RT

here, delta n= 5 - 7/2= -1.5

temp T = 27 + 273= 300 k

delta H - delta E = -1.5 × 8.314 × 300

= -3741.3 joule

The value of delta H - delta E is - 3741.3 joule and since value is negative it implies that delta E is greater than that of delta H.