Question

At 27 degree c the present of the gas X is 12 atm at _73 degrees c the pressure of resulting gas is

Answer 1

Answer: 8 atm

Explanation:

( I took the second temperature as -72°C )

So from Ideal Gas equation,

PV=nRT

Under constant volume,

P ∝ T

So,

P1/T1 = P2/T2

Given,

P1 = 12 atm

T1 = 27°C = 300 K

P2 = ?

T2 = -73°C = 200 K

So,

12/300 = P2/200

=>P2 = 8 atm

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