Question

At 27° c, the ratio of R.M.S velocity of ozone to So2​

Answer 1

Answer: At 27° c, the ratio of R.M.S velocity of ozone to $SO_2​$ is 0.96.

Explanation:

The formula used for root mean square speed is:

$\nu_{rms}=\sqrt{\frac{3RT}{M}}$

where,

$\nu_{rms}$ = root mean square speed

R = Gas constant = $8.314J/Kmol$

T = temperature = $27^0C=(27+273)=300K$

M = atomic mass

Now put all the given values in the above root mean square speed formula, we get:

$\nu_{rms}{O_3}=\sqrt{\frac{3\times 8.314J/Kmol\times (300K)}{0.048kg/mol}}$

$\nu_{rms}{O_3}=394.8m/s$

$\nu_{rms}{SO_2}=\sqrt{\frac{3\times 8.314J/Kmol\times (300K)}{0.044kg/mol}}$

$\nu_{rms}{SO_2}=412.4m/s$

$\frac{\nu_{rms}{O_3}}{\nu_{rms}{SO_2}}=\frac{394.8}{412.4}=0.96$

At 27° C, the ratio of R.M.S velocity of ozone to $SO_2$ is 0.96.