At 27°c a sample of ammonia gas exerts pressure of 5.3 atmospheric pressure.what is the pressure when the volume of the gas is reduced to to one tenth of the original value at the same temperature
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Answer:
53 atm
Explanation:
Temperature, T = 270C or 300 K
Initial Pressure, P1 = 5.3 atm
Initial volume, V1 = V
Final Volume, V2 = V / 10
Final Pressure, P2 = ?
As we know
PV = nRT
For given number of moles at constant temperature Pressure is inversely proportional to Volume of gas. We can write
P1/P2=V2/V1
P2=P1×V1/V2
=5.3×V×10/V
=53 atm
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