Chemistry, asked by vemularajender2124, 7 days ago

At 27°c, and 1 atom pressure a gaseous mix. of Co₂, co, So₂ gives 2:1:3 volume 2 ratio, Calculate the number of moles in 30gm of the mixture.​

Answers

Answered by suvarnasonar32
1

Answer:

Let the mixture has 100g as total mass.

The masses of CO and CO

2

are 90.55g and 100−90.55=9.45 g respectively.

The number of moles of CO are

28

90.55

=3.234.

The number of moles of CO

2

are

44

9.45

=0.215.

The mole fraction of CO is

3.234+0.215

3.234

=0.938.

The mole fraction of CO

2

is 1−0.938=0.062.

The partial pressure of CO is the product of the mole fraction of CO and the total pressure.

It is 0.938×1=0.938 atm.

The partial pressure of carbon dioxide is 0.062×1=0.042 atm.

The expression for the equilibrium constant is:

K

p

=

P

CO

2

P

CO

2

=

0.062

(0.938)

2

=14.19

Δn

g

=2−1=1

K

c

=K

p

(RT)

−Δn

=14.19×(0.0821×1127)

−1

=0.153.

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