Question

At 27°C if the solubility product of
M(OH), is 3.2 x 10-11, its solubility in
gL-1 is (molar mass of M(OH), is 58 g
mol-1)
(1) 2 x 10-4 (2) 1.16 x 10-14
(3) 1.16 x 10-2 (4) 5.8 x 10-3​

Answer 1

Answer:

Explanation:

Hey baby this is easy to solve

Ksp=4s^3

Then you get s but we have to find s in grams per litre

You get s=2×10^-4

Then on converting you get

Ans =1.16×10^-2