Question

At 27°C temperature the volume of O2 gas is 6 l . At which temperature will the volume of O2 gas be half

Answer 1

Answer:

Given V1 = 1 litre

P1 = 1 atm

V2 = ?

P2 = 750 / 760 atm

Using

P1V1 = P2V2

We get

1 × 1 = 750 / 760 × V2

V2 = 1.0133 litre = 1013.3 ml

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