Question

At 27°C the internal energy change of reaction H2(g) + Cl2(g) → 2HCl(g) is 2Cal. What is the enthalpy change of
this reaction?​

Answer 1

Answer:

Here is the answer

Explanation:

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Answer 2

The value of enthalpy change is 2 cal.

Explanation:

Internal energy and enthalpy change of the reaction are related according to the following relationship

$\Delta H = \Delta U + \Delta _{ng}RT$

In the given reaction $\Delta H = ?$

$\Delta U = 2 Cal$

The change in the number of moles as can be seen in the equation is zero.

There are two gaseous reactant molecules and two gaseous product molecules.

$\Delta _{ng} = 2-(1+1) = 0$

Hence $\Delta H = \Delta U + 0\times RT$

$\Delta H = \Delta U = 2 cal$