Question

. At 27°C the total kinetic energy of 8 grams
Hydrogen is .......... times, the total kinetic
energy of 8 grams of oxygen
1) 2
2) 4
3) 8 4) 16
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Answer 1

Answer:

pV=nRT (formula)

Explanation:

answer is 16

8g each of oxygen and hydrogen at 27°C will have the total kinetic energy in the ratio of 1 : 16.

therefore option 4) 16 is correct

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Answer 2

Answer:

The hydrogen's kinetic energy is $16$ times to the kinetic energy of oxygen at equal masses.

Therefore, option 4) $16$ times is the correct choice.

Explanation:

Give,

The mass of hydrogen = $8 g$

The mass of oxygen = $8 g$

The temperature is kept constant at $27\textdegree C$

Let the total kinetic energy of hydrogen be X times the total kinetic energy of oxygen.

As we know,

• If the gases have equal masses at a constant temperature, the kinetic energy is inversely proportional to the molecular weights of the gases.

Therefore,

• $\frac{K.E_{1} }{K.E_{2} } = \frac{Molecular weight of 2}{Molecular weight of 1}$       -------equation (1)

Here,

• K.E₁ = The hydrogen's kinetic energy
• K.E₂ = The kinetic energy of oxygen
• The molecular weight of 1 ( hydrogen ) = $1g/mol$
• The molecular weight of 2 ( oxygen ) = $16g/mol$

After putting the values in the equation (1), we get:

• $\frac{K.E_{1} }{K.E_{2} } = \frac{16}{1}$
• $K.E_{1} = 16K.E_{2}$

Therefore, the kinetic energy of hydrogen is $16$ times the kinetic energy of oxygen.