Chemistry, asked by kumkummaurya2003, 9 months ago

at 291k the molar conductance values at infinite dilution of NH4Cl ,NAOH and Nacl are 129.1,217.4 nd 108.3 s cm² mol-² resp. calculate pf NH4OH at infinite dilution - solution

Answers

Answered by Mahidharprapanjay

0

Explanation:

2584594.694395

is the correct answer

Answered by 19p0178

2

Answer:

238.2Scm2mol−1

Explanation:

Λ∞m(NH4OH)= Λ∞m(NH4Cl)+ Λ∞m(NaOH)− Λ∞m(NaCl)

=(129.1+217.4−108.3) S cm2mol−1

=238.2 S cm2mol−1

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