Physics, asked by chhuganiyash1, 9 months ago

At 298 K, 500cm3 H20 dissolved
15.30 cm3 CH4(STP) under a
partial pressure of methane of
one atm. If Henery's law holds,
what pressure is required to
cause 0.001 mole methane to
dissolve in 300cm3 water?
(a) 0.286 atm
(b) 2.486 atm
(c) 1.286 atm
(d) 3.111 atm​

Answers

Answered by topwriters
6

(b) 2.486 atm

Explanation:

Given: At 298 K, 500cm3 H20 dissolved 15.30 cm3 methane (STP) under a partial pressure of methane of one atm.

Find: What pressure is required to cause 0.001 mole methane to dissolve in 300cm3 water.

Solution: Applying the concept of Dalton’s Law of Partial Pressure / Henry's law, the required pressure to cause 0.001 mole methane to dissolve in 300cm3 water is 2.486 atm.

Option B is the answer.

Answered by akshayaranjith603
20

Answer:getting an approximate answer

Explanation:

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