Question

At 298 K, the osmotic pressure of a glucose solution is 10.50 atm. Calculate the freezing point of the solution. The density of the solution is 1.16 g/mL

Answer 1

Explanation:

The osmotic pressure is given by Π=CRT

30=C×0.08206×298

C=1.23 M

Assuming the density of the solution to be 1 g/ml, we can approximate molarity and molality.

C=1.23 m

The depression in the freezing point =ΔT

f

=K

f

m=1.86×1.23=2.28

o

C

The freezing point of pure water is 0

o

C.

The freezing point of solution =0−2.28=−2.28

o

C