At 298 k the specific rate constant for the hydrolysis of ethyl acetate by NaOH is 6.36 lit.Mol' min starting with concentration of base and ester of 0.01 mol lit.'' what proportion of ester will be hydrolyzed in 20 min.?
Answers
Answered by
0
Answer:
Solution
answer:- The initial rate or the reaction when the base and the ester have concentration
rate=k[A]
0
[B]
0
=6.36 litre mol
−1
min
−1
×0.02 mol litre
−1
×0.02 mol litre
−1
=0.002544 mol litre
−1
min
−1
(b) Since the concentrations of two reactants are same, the reaction A+B→products can be approximated to 2A→products
Hence, the following expression can be applied.
[A]
1
=
[A]
0
1
+kt
[A]
1
=
0.02
1
+6.36×10=56.36
[A]=0.0177M
The rate of reaction, 10 minute after the commencement of the reaction,
rate=k[A][B]=6.36 litre mol
−1
min
−1
×0.0177 mol litre
−1
×0.0177 mol litre
−1
=0.002002 mol litre
−1
min
−1
Similar questions