Question

At 298 k the vapour pressure of pure benzene is 0.256 bar and the vapour pressure of pure toulene is 0.095bar if the mole fraction of benzene is 0.40 what is the total vapour pressure of solution calculate the composition of vapour in terms of mole fraction

Answer 1

Solution in the attachment, hope it helped...

Answer 2

Concept Introduction: Vapour pressure is the pressure executed by the Vapours.

Given:

We have been Given: Vapour Pressure of Benzene

$0.256 \: bar$

Vapour pressure of Toluene

$0.095 \: bar$

Mole Fraction of Benzene is

$0.40$

To Find:

We have to Find: Total Vapour Pressure of Solution and Composition of Vapour in terms of Mole Fraction.

Solution:

According to the problem, Mole Fraction of Toluene is

$mole \: fraction \: of \: benzene = 1 - mole \: fraction \: of \: toluene \\ = 1 - 0.40 = 0.60$

therefore total Vapour Pressure will be,

$0.256 + 0.095 = 0.351 \: bar$

Final Answer: Total Vapour is

$0.351 \: bar$

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