At 298 k what will be the change in standard internal energy change for the given reaction
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Calculate standard internal energy change for the reaction OF2 H2O ---------- O2 2HF at 298K Standard enthalpy of formation of OF2 is
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At 298 K what will be the change in standard internal energy change for the given reaction OF2(g) + H2O(g) -> O2( g) + 2HF(g) Δ H = - 310 k J (A) - 312.5 kJ (B
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