Question

at 298 Kelvin temperature 8 gram of methanol and 15 gram of acetic acid combined together in a 500 ml solution find the mole fraction of each component

Answer 1

Mole fraction of methanol and acetic acid is same, 0.5.

Explanation:

Suppose mole fraction of methanol = $X_{A}$ ,

mole fraction of acetic acid = $X_{B}$

Molecular weight of methanol = 32

Molecular weight of acetic acid = 32

$X_{A}$ = number of moles of A / ( number of moles of A+number of moles of B)

Number of moles of A = Weight/ Molecular weight = 8/32 =0.25

$X_{A}$ = 0.25/(0.25+0.25) = 0.5

$X_{B}$ = number of moles of B / ( number of moles of A+number of moles of B)

Number of moles of B = 15/60 =0.25

$X_{B}$ = 0.25/(0.25+0.25) = 0.5

Answer 2

Answer:

ok

Explanation: