Chemistry, asked by yashvardhan6427, 9 months ago

At 298 kelvin temperature it drama methanol and 15 gram of acetic acid combined together in a 500 ml of solution find the mole fraction of each component

Answers

Answered by Kingsman24
0

Answer:

Suppose mole fraction of methanol = ,

mole fraction of acetic acid =

Molecular weight of methanol = 32

Molecular weight of acetic acid = 32

= number of moles of A / ( number of moles of A+number of moles of B)

Number of moles of A = Weight/ Molecular weight = 8/32 =0.25

= 0.25/(0.25+0.25) = 0.5

= number of moles of B / ( number of moles of A+number of moles of B)

Number of moles of B = 15/60 =0.25

= 0.25/(0.25+0.25) = 0.5

Explanation:

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