Question

at 298 Kelvin the resistance of 0.5 normality sodium hydroxide solution is 35 ohm the cell constant is 0.503/cm the electrical conductivity of the solution is​

Answer 1

Answer:

Explanation:

Molar conductivity= k×1000/M

conductivity (k)= cell constant×1/resistance

=0.367×1/31.6=0.011

^M= 0.011×1000/0.05=220