Chemistry, asked by anArohi123, 1 year ago

At 298K,equal amount of sulphur dioxide (SO2),methane(CH4)and oxygen (O2)are mixed in empty container.Find the ratio of their number of moles.

Answers

Answered by Anonymous
8

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Answered by KrishnaShiwal
0

Hii

here is your answer

Partial pressure is directly proportional to the mole fraction of the gas in the mixture.

Partial pressure = total pressure x mole fraction

Here let the mass of each gas be X gm.

Molecular mass of SO2 - 64

" " " of CH4 - 16

" " of O2- 32.

Moles of SO2 - X / 64

Moles kf CH4 - X / 16

Moles of O2 - X / 32.

TOTAL MOLES OF MIXTURE- 7X / 64

Hence partial pressure = (X / 16) / (7X / 64) * 2.1 = 4 / 7 * 2.1 = 1.2 atm.

Thumps up if u understood.

Good luck.

Hope it helps

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anArohi123: I have asked to find out the no. of moles
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