Question

At 298k temperature, in case of dissociation of N2O4, the partial pressure of N2O4 is 0.8 atm and Kp of the reaction is 0.008 atm find out Kc and partial pressure of NO2 for the reaction.​

Answer 1

Answer:

Given that,

N

2

O

4

(g)⇋2NO

2

(g)

1−x 2x ------ At equilibrium

Now,

P

NO

2

=P×X

NO

2

n

T

=1−x+2x=1+x

X

NO

2

=

n

T

nX

NO

2

=

1+x

2x

The partial pressure of NO

2

is given as:

P

NO

2

=

1+x

2x

P

Option A is correct.

Explanation:

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