Question

At 2pm the height of a pole is √3 times the length of its shadow on the level ground.at the same time, what will be the length of the shadow of a 40m high tower​

Answer 1

Answer:

Let the height of the tower be h

∴height of the shadow=

3

h

In a △ABC,

tan∠ACB=

3

h

h

⇒tan∠ACB=

3

1

∴∠ACB=60

∘

Therefore, angle of elevation is 30

∘

.