Question

At 300 K, 36 g of glucose present per litre in its
solution has an osmotic pressure of 4.98 bar. If the
osmotic pressure of solution is 1.52 bar at the
same temperature, what would be its
concentration?​

Answer 1

Answer:

concentration of 2nd solution is 0.0061 M

Explanation:

Here we have given

π1= 4.98

π2 = 1.52

C1 = 36/180

C2 = ? (we have to find)

Now according to van’t hoff equation

Π = CRT

Putting the values in above equation,we get

4.98 = 36/180RT ------------------------1

1.52 = c2RT       ------------------------2

Now dividing equation 2 by 1 ,we get

(c2 x 180) / 36 = 1.52 / 4.98

or

c2 = 0.0061