Question

At 300 K temperature pressure of 2.5 gram N2 gas is 4 bar and volume 2.5 L. It pressure becomes 10 bar then calculate its volume at same temperature.
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Answer 1

Answer:

P= 1/V

P1 V1= P2 V2

V2= P1 V1/P2

4×2.5/10 = 1 L

Answer 2

Answer:

V2=1L

Explanation:

P1 = 4bar

V1 = 2.5L

P2 = 10 bar

V2 = ???

We know that,

∴ P1V1 = P2V2

∴ 4*2.5 = 10*V2

∴ V2 = 4*2.5/10

∴ V2 = 1L

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