Question

at 300 k the volume of the flask that contains a gaseous mixture of two gases X is 20 L if the total pressure of the container is 2 atm 0.1 mole and Y is 20 L if the total pressure of the container is 2 atm and 0.1 mole of X is present calculate the partial pressure of gas Y (R= 0.0821 L atm /mol K

Answer 1

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$\mathbf{Total\: moles =}$ $\tt\frac{PV}{RT}$

= $\tt\frac{2\: ×\: 10}{298\: × \:0.0821}$

$\mathbf{ =0.8174}$

$\mathbf{Moles of CO² =0.8174−0.2=0.6174}$

Partial pressure of CO= X co ×2= $\tt\frac{0.2}{0.8174}$ $\mathbf{×2=0.4893 atm}$

$\mathbf{Partial pressure of CO² =2−0.4893=}$

$\mathbf{=1.51}$