Question

At 300 kelvin 30g of glucose resent in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of glucose solution is 1.52bar what would be the concentration

Answer 1

Question -

At 300 kelvin 30g of glucose resent in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of glucose solution is 1.52bar what would be the concentration

Answer -

$\Large \bf{Case - 1}$

$\Large \sf{π} = \frac{W_2}{M_2} × \frac{RT}{V}$

Where $\sf{W_2}$ = Given mass of solute

$\sf{M_2}$ = Molar mass of solute

V = Volume of solvent

$\sf{M_2}$ for $\bf{C_6H_12O_6}$

= 6×12+12×1+6×16

= 72+12+96

= 84+96

= 180g

Now, put in formula

$\Large \sf{4.98} = \frac{36}{180} × \frac{300R}{1}$ ............(1)

$\Large \bf{Case - 2}$

$\Large \sf{1.52} = \frac{C×R×300}{1}$.........(2)

Now by dividing both equation,

$\Large \sf \frac{4.98}{1.52} = \frac{36}{180} × \frac{300R}{300RC}$

$\Large \sf \frac{4.98}{1.52} × \frac{180}{36} = \frac{1}{C}$

$\Large \sf{C} = 0.061 M$