Chemistry, asked by sreyanair3073, 1 day ago

At 300°K, the vapor pressure of pure benzene (C6H6) is 0.1355 atm and the vapor pressure of pure n-hexane (C6H14) is 0.2128 atm. Mixing 50.0 g benzene with 50.0 g of n-hexane gives a solution that is nearly ideal. If this vapor were collected and then recondensed, the mole fraction of benzene in this new solution would be 0.414.

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Answered by keumalanitanmay
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Answer:

At 300°K, the vapor pressure of pure benzene (C6H6) is 0.1355 atm and the vapor pressure of pure n-hexane (C6H14) is 0.2128 atm. Mixing 50.0 g benzene with 50.0 g of n-hexane gives a solution that is nearly ideal.

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