At 30°C, the resistance of a conductor is 5 ohm. Find
the temperature at which the resistance becomes
5.2ohm.
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temperature at 5.2 ohm is 70°C.
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Answer:
temperature of 5.2 Ω is 70°
Explanation:
Given that :-
R = resistance of temp T = 30c
α= temp of coefficient at resistance = 5
R = resistance of temp= T= ?
α= temp of coefficient at resistance = 5.2
Here,
5 = R (1+30α)......(1)
5.2 = R (1+α)......(2)
temperature of 5.2 Ω is 70°
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