At 300k& an ideal solution is formed by
mixing 460g of toluene with 390 g benzene
the vapor pressure of pure toluene
and benzene at 300k are 32 and 40mm
mole fraction of toulene in vapour phase
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Answer:
Number of moles is the ratio of mass to molar mass.
The molar masses of benzene and toluene are 78 g/mol and 92 g/mol respectively.
Number of moles of benzene =
78
80
=1.026
Number of moles of toluene =
92
100
=1.087
Mole fraction of benzene, X
B
=
1.026+1.087
1.026
=0.486
Mole fraction of toluene, X
T
=1−0.486=0.514
P
B
=P
B
o
×X
B
=50.71×0.486=24.65 mm Hg
P
T
=P
T
o
X
T
=32.06×0.514=16.48 mm of Hg
Total vapour pressure =24.65+16.48=41.13 mm Hg
Mole fraction of benzene in vapour phase is as follows:
Y
B
=
41.13
24.65
=0.60
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