At 300k and
1 atm 15ml
of
gaseous hydrocarbons
requires 375ml air
Containing 20% of oxygen
by volume for Complete Combustion. After Combo-
stion the gases occupy 330ml
Assuming that
the water
is in liquid form and the volumes were measured at the same temperature and pressure the formula of hydrocarbon is.......
Answers
Answered by
1
375 ml of 20% oxygen corresponds to 375×
100
20
=75mL.
The ratio of the volume of oxygen used for combustion to volume of hydrocabon =
15
75
=
1
5
.
This ratio can be obtained with propane.
C
3
H
8
+5O
2
→3CO
2
+4H
2
O
Water is in the liquid form.
15 ml of propane on combustion will give 3×15=45 mL of carbon dioxide.
375−75=300 ml of air (except oxygen) will remain.
Total volume will be 300+45=345.
Some carbon dioxide will dissolve in liquid water. Hence, the total volume will be less than 345 mL. This explains a volume of 330 mL.
Hence, the correct option is A
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